0,5q^2+5q+3=0

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Solution for 0,5q^2+5q+3=0 equation: 



0.5q^2+5q+3=0

a = 0.5; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·0.5·3
Δ = 19
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{19}}{2*0.5}=\frac{-5-\sqrt{19}}{1}
$


$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{19}}{2*0.5}=\frac{-5+\sqrt{19}}{1}
$

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